3(2-5)=5(z+4)

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Solution for 3(2-5)=5(z+4) equation: 



3(2-5)=5(z+4)

We move all terms to the left:

3(2-5)-(5(z+4))=0

We add all the numbers together, and all the variables

-(5(z+4))+3(-3)=0

We add all the numbers together, and all the variables

-(5(z+4))-9=0



We calculate terms in parentheses: -(5(z+4)), so:

5(z+4)

We multiply parentheses

5z+20

Back to the equation:

-(5z+20)



We get rid of parentheses

-5z-20-9=0

We add all the numbers together, and all the variables

-5z-29=0

We move all terms containing z to the left, all other terms to the right

-5z=29

z=29/-5

z=-5+4/5

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