3(2-b)+2(b+3)=15

Solution for 3(2-b)+2(b+3)=15 equation:

Simplifying
3(2 + -1b) + 2(b + 3) = 15
(2 * 3 + -1b * 3) + 2(b + 3) = 15
(6 + -3b) + 2(b + 3) = 15

Reorder the terms:
6 + -3b + 2(3 + b) = 15
6 + -3b + (3 * 2 + b * 2) = 15
6 + -3b + (6 + 2b) = 15

Reorder the terms:
6 + 6 + -3b + 2b = 15

Combine like terms: 6 + 6 = 12
12 + -3b + 2b = 15

Combine like terms: -3b + 2b = -1b
12 + -1b = 15

Solving
12 + -1b = 15

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1b = 15 + -12

Combine like terms: 12 + -12 = 0
0 + -1b = 15 + -12
-1b = 15 + -12

Combine like terms: 15 + -12 = 3
-1b = 3

Divide each side by '-1'.
b = -3

Simplifying
b = -3