3(2-b)-1=4(3-b)

Solution for 3(2-b)-1=4(3-b) equation:

3(2-b)-1=4(3-b)

We move all terms to the left:

3(2-b)-1-(4(3-b))=0

We add all the numbers together, and all the variables

3(-1b+2)-(4(-1b+3))-1=0

We multiply parentheses

-3b-(4(-1b+3))+6-1=0


We calculate terms in parentheses: -(4(-1b+3)), so:

4(-1b+3)

We multiply parentheses

-4b+12

Back to the equation:

-(-4b+12)


We add all the numbers together, and all the variables

-3b-(-4b+12)+5=0

We get rid of parentheses

-3b+4b-12+5=0

We add all the numbers together, and all the variables

b-7=0

We move all terms containing b to the left, all other terms to the right

b=7