3(2-c)=-(c+40

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Solution for 3(2-c)=-(c+40 equation: 



3(2-c)=-(c+40

We move all terms to the left:

3(2-c)-(-(c+40)=0

We add all the numbers together, and all the variables

3(-1c+2)-(-(c+40)=0

We multiply parentheses

-3c-(-(c+40)+6=0

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