3(2-g)+16=2(g-10)+2

Solution for 3(2-g)+16=2(g-10)+2 equation:

3(2-g)+16=2(g-10)+2

We move all terms to the left:

3(2-g)+16-(2(g-10)+2)=0

We add all the numbers together, and all the variables

3(-1g+2)-(2(g-10)+2)+16=0

We multiply parentheses

-3g-(2(g-10)+2)+6+16=0


We calculate terms in parentheses: -(2(g-10)+2), so:

2(g-10)+2

We multiply parentheses

2g-20+2

We add all the numbers together, and all the variables

2g-18

Back to the equation:

-(2g-18)


We add all the numbers together, and all the variables

-3g-(2g-18)+22=0

We get rid of parentheses

-3g-2g+18+22=0

We add all the numbers together, and all the variables

-5g+40=0

We move all terms containing g to the left, all other terms to the right

-5g=-40

g=-40/-5

g=+8