3(2-r)+4(1-r)=3(5-r)

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Solution for 3(2-r)+4(1-r)=3(5-r) equation:



3(2-r)+4(1-r)=3(5-r)
We move all terms to the left:
3(2-r)+4(1-r)-(3(5-r))=0
We add all the numbers together, and all the variables
3(-1r+2)+4(-1r+1)-(3(-1r+5))=0
We multiply parentheses
-3r-4r-(3(-1r+5))+6+4=0
We calculate terms in parentheses: -(3(-1r+5)), so:
3(-1r+5)
We multiply parentheses
-3r+15
Back to the equation:
-(-3r+15)
We add all the numbers together, and all the variables
-7r-(-3r+15)+10=0
We get rid of parentheses
-7r+3r-15+10=0
We add all the numbers together, and all the variables
-4r-5=0
We move all terms containing r to the left, all other terms to the right
-4r=5
r=5/-4
r=-1+1/4

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