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3(2-x)+2+4x=1-(x-(2+x)-1)
We move all terms to the left:
3(2-x)+2+4x-(1-(x-(2+x)-1))=0
We add all the numbers together, and all the variables
3(-1x+2)+4x-(1-(x-(x+2)-1))+2=0
We add all the numbers together, and all the variables
4x+3(-1x+2)-(1-(x-(x+2)-1))+2=0
We multiply parentheses
4x-3x-(1-(x-(x+2)-1))+6+2=0
We calculate terms in parentheses: -(1-(x-(x+2)-1)), so:We add all the numbers together, and all the variables
1-(x-(x+2)-1)
determiningTheFunctionDomain -(x-(x+2)-1)+1
We calculate terms in parentheses: -(x-(x+2)-1), so:We add all the numbers together, and all the variables
x-(x+2)-1
We get rid of parentheses
x-x-2-1
We add all the numbers together, and all the variables
-3
Back to the equation:
-(-3)
4
Back to the equation:
-(4)
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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