3(2-x)+5(6x-3)=16(x-4)

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Solution for 3(2-x)+5(6x-3)=16(x-4) equation: 



3(2-x)+5(6x-3)=16(x-4)

We move all terms to the left:

3(2-x)+5(6x-3)-(16(x-4))=0

We add all the numbers together, and all the variables

3(-1x+2)+5(6x-3)-(16(x-4))=0

We multiply parentheses

-3x+30x-(16(x-4))+6-15=0



We calculate terms in parentheses: -(16(x-4)), so:

16(x-4)

We multiply parentheses

16x-64

Back to the equation:

-(16x-64)



We add all the numbers together, and all the variables

27x-(16x-64)-9=0

We get rid of parentheses

27x-16x+64-9=0

We add all the numbers together, and all the variables

11x+55=0

We move all terms containing x to the left, all other terms to the right

11x=-55

x=-55/11

x=-5

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