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3(2-x)-5(x-2)=x-2(3-x
We move all terms to the left:
3(2-x)-5(x-2)-(x-2(3-x)=0
We add all the numbers together, and all the variables
3(-1x+2)-5(x-2)-(x-2(-1x+3)=0
We multiply parentheses
-3x-5x-(x-2(-1x+3)+6+10=0
We add all the numbers together, and all the variables
-8x-(x-2(-1x+3)+6+10=0
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