3(2-x)-5(x-2)=x-2(3-x)

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Solution for 3(2-x)-5(x-2)=x-2(3-x) equation: 



3(2-x)-5(x-2)=x-2(3-x)

We move all terms to the left:

3(2-x)-5(x-2)-(x-2(3-x))=0

We add all the numbers together, and all the variables

3(-1x+2)-5(x-2)-(x-2(-1x+3))=0

We multiply parentheses

-3x-5x-(x-2(-1x+3))+6+10=0



We calculate terms in parentheses: -(x-2(-1x+3)), so:

x-2(-1x+3)

We multiply parentheses

x+2x-6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

-8x-(3x-6)+16=0

We get rid of parentheses

-8x-3x+6+16=0

We add all the numbers together, and all the variables

-11x+22=0

We move all terms containing x to the left, all other terms to the right

-11x=-22

x=-22/-11

x=+2

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