3(2-z)/2=-z

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Solution for 3(2-z)/2=-z equation:


z in (-oo:+oo)

(3*(2-z))/2 = -z // + z

(3*(2-z))/2+z = 0

(3*(2-z))/2+(2*z)/2 = 0

3*(2-z)+2*z = 0

6-z = 0

(6-z)/2 = 0

(6-z)/2 = 0 // * 2

6-z = 0

6-z = 0 // - 6

-z = -6 // * -1

z = 6

z = 6

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