3(2/3c+4)=-(c-4)

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Solution for 3(2/3c+4)=-(c-4) equation: 



3(2/3c+4)=-(c-4)

We move all terms to the left:

3(2/3c+4)-(-(c-4))=0



Domain of the equation: 3c+4)!=0

c∈R



We multiply parentheses

6c-(-(c-4))+12=0



We calculate terms in parentheses: -(-(c-4)), so:

-(c-4)

We get rid of parentheses

-c+4

We add all the numbers together, and all the variables

-1c+4

Back to the equation:

-(-1c+4)



We get rid of parentheses

6c+1c-4+12=0

We add all the numbers together, and all the variables

7c+8=0

We move all terms containing c to the left, all other terms to the right

7c=-8

c=-8/7

c=-1+1/7

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