3(2/3c+4)=-5(c-4)

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Solution for 3(2/3c+4)=-5(c-4) equation: 



3(2/3c+4)=-5(c-4)

We move all terms to the left:

3(2/3c+4)-(-5(c-4))=0



Domain of the equation: 3c+4)!=0

c∈R



We multiply parentheses

6c-(-5(c-4))+12=0



We calculate terms in parentheses: -(-5(c-4)), so:

-5(c-4)

We multiply parentheses

-5c+20

Back to the equation:

-(-5c+20)



We get rid of parentheses

6c+5c-20+12=0

We add all the numbers together, and all the variables

11c-8=0

We move all terms containing c to the left, all other terms to the right

11c=8

c=8/11

c=8/11

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