3(2/3w-10)=(1/2+5w)3

Solution for 3(2/3w-10)=(1/2+5w)3 equation:

3(2/3w-10)=(1/2+5w)3

We move all terms to the left:

3(2/3w-10)-((1/2+5w)3)=0


Domain of the equation: 3w-10)!=0

w∈R



Domain of the equation: 2+5w)3)!=0

We move all terms containing w to the left, all other terms to the right

5w)3)!=-2

w!=-2/1

w!=-2

w∈R


We add all the numbers together, and all the variables

3(2/3w-10)-((+5w+1/2)3)=0

We multiply parentheses

6w-((+5w+1/2)3)-30=0

We multiply all the terms by the denominator


6w*2)3)-((+5w+1-30*2)3)=0

We add all the numbers together, and all the variables

6w*2)3)-((5w-59)3)=0

We add all the numbers together, and all the variables

6w*2)3)-((5w=0

Wy multiply elements

12w^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{24}=0$