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3(2/3x+9)=-2(5x+9/2)
We move all terms to the left:
3(2/3x+9)-(-2(5x+9/2))=0
Domain of the equation: 3x+9)!=0We add all the numbers together, and all the variables
x∈R
3(2/3x+9)-(-2(+5x+9/2))=0
We multiply parentheses
6x-(-2(+5x+9/2))+27=0
We multiply all the terms by the denominator
6x*2))-(-2(+5x+9+27*2))=0
We add all the numbers together, and all the variables
6x*2))-(-2(5x+63))=0
We add all the numbers together, and all the variables
6x*2))-(-2(5x=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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