3(20+4x)=6x+6

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Solution for 3(20+4x)=6x+6 equation: 



3(20+4x)=6x+6

We move all terms to the left:

3(20+4x)-(6x+6)=0

We add all the numbers together, and all the variables

3(4x+20)-(6x+6)=0

We multiply parentheses

12x-(6x+6)+60=0

We get rid of parentheses

12x-6x-6+60=0

We add all the numbers together, and all the variables

6x+54=0

We move all terms containing x to the left, all other terms to the right

6x=-54

x=-54/6

x=-9

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