3(20c-12)=4(11c-17)

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Solution for 3(20c-12)=4(11c-17) equation: 



3(20c-12)=4(11c-17)

We move all terms to the left:

3(20c-12)-(4(11c-17))=0

We multiply parentheses

60c-(4(11c-17))-36=0



We calculate terms in parentheses: -(4(11c-17)), so:

4(11c-17)

We multiply parentheses

44c-68

Back to the equation:

-(44c-68)



We get rid of parentheses

60c-44c+68-36=0

We add all the numbers together, and all the variables

16c+32=0

We move all terms containing c to the left, all other terms to the right

16c=-32

c=-32/16

c=-2

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