3(20x)+100=1020

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Solution for 3(20x)+100=1020 equation: 



3(20x)+100=1020

We move all terms to the left:

3(20x)+100-(1020)=0

We add all the numbers together, and all the variables

320x-920=0

We move all terms containing x to the left, all other terms to the right

320x=920

x=920/320

x=2+7/8

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