3(20x-5)-17*3=(120-600)*5+7x

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Solution for 3(20x-5)-17*3=(120-600)*5+7x equation: 



3(20x-5)-17*3=(120-600)*5+7x

We move all terms to the left:

3(20x-5)-17*3-((120-600)*5+7x)=0

We add all the numbers together, and all the variables

3(20x-5)-((-480)*5+7x)-17*3=0

We add all the numbers together, and all the variables

3(20x-5)-((-480)*5+7x)-51=0

We multiply parentheses

60x-((-480)*5+7x)-15-51=0



We calculate terms in parentheses: -((-480)*5+7x), so:

(-480)*5+7x

determiningTheFunctionDomain
7x+(-480)*5

We add all the numbers together, and all the variables

7x-2400

Back to the equation:

-(7x-2400)



We add all the numbers together, and all the variables

60x-(7x-2400)-66=0

We get rid of parentheses

60x-7x+2400-66=0

We add all the numbers together, and all the variables

53x+2334=0

We move all terms containing x to the left, all other terms to the right

53x=-2334

x=-2334/53

x=-44+2/53

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