3(23-2b)+3b=48.b=

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Solution for 3(23-2b)+3b=48.b= equation: 



3(23-2b)+3b=48.b=

We move all terms to the left:

3(23-2b)+3b-(48.b)=0

We add all the numbers together, and all the variables

3(-2b+23)+3b-(+48.b)=0

We add all the numbers together, and all the variables

3b+3(-2b+23)-(+48.b)=0

We multiply parentheses

3b-6b-(+48.b)+69=0

We get rid of parentheses

3b-6b-48.b+69=0

We add all the numbers together, and all the variables

-51b+69=0

We move all terms containing b to the left, all other terms to the right

-51b=-69

b=-69/-51

b=1+6/17

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