3(23-2b)+3b=48.b=

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Solution for 3(23-2b)+3b=48.b= equation:



3(23-2b)+3b=48.b=
We move all terms to the left:
3(23-2b)+3b-(48.b)=0
We add all the numbers together, and all the variables
3(-2b+23)+3b-(+48.b)=0
We add all the numbers together, and all the variables
3b+3(-2b+23)-(+48.b)=0
We multiply parentheses
3b-6b-(+48.b)+69=0
We get rid of parentheses
3b-6b-48.b+69=0
We add all the numbers together, and all the variables
-51b+69=0
We move all terms containing b to the left, all other terms to the right
-51b=-69
b=-69/-51
b=1+6/17

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