3(23-2x)+3=48

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Solution for 3(23-2x)+3=48 equation: 



3(23-2x)+3=48

We move all terms to the left:

3(23-2x)+3-(48)=0

We add all the numbers together, and all the variables

3(-2x+23)+3-48=0

We add all the numbers together, and all the variables

3(-2x+23)-45=0

We multiply parentheses

-6x+69-45=0

We add all the numbers together, and all the variables

-6x+24=0

We move all terms containing x to the left, all other terms to the right

-6x=-24

x=-24/-6

x=+4

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