3(23-2x)+3x=48*

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Solution for 3(23-2x)+3x=48* equation:



3(23-2x)+3x=48*
We move all terms to the left:
3(23-2x)+3x-(48*)=0
We add all the numbers together, and all the variables
3(-2x+23)+3x-0=0
We add all the numbers together, and all the variables
3x+3(-2x+23)=0
We multiply parentheses
3x-6x+69=0
We add all the numbers together, and all the variables
-3x+69=0
We move all terms containing x to the left, all other terms to the right
-3x=-69
x=-69/-3
x=+23

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