3(23b-2b)+3b=16

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Solution for 3(23b-2b)+3b=16 equation: 



3(23b-2b)+3b=16

We move all terms to the left:

3(23b-2b)+3b-(16)=0

We add all the numbers together, and all the variables

3(+21b)+3b-16=0

We add all the numbers together, and all the variables

3b+3(+21b)-16=0

We multiply parentheses

3b+63b-16=0

We add all the numbers together, and all the variables

66b-16=0

We move all terms containing b to the left, all other terms to the right

66b=16

b=16/66

b=8/33

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