3(24-y)+y=40

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Solution for 3(24-y)+y=40 equation: 



3(24-y)+y=40

We move all terms to the left:

3(24-y)+y-(40)=0

We add all the numbers together, and all the variables

3(-1y+24)+y-40=0

We add all the numbers together, and all the variables

y+3(-1y+24)-40=0

We multiply parentheses

y-3y+72-40=0

We add all the numbers together, and all the variables

-2y+32=0

We move all terms containing y to the left, all other terms to the right

-2y=-32

y=-32/-2

y=+16

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