3(27/10)+y=12

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Solution for 3(27/10)+y=12 equation:



3(27/10)+y=12
We move all terms to the left:
3(27/10)+y-(12)=0
determiningTheFunctionDomain y-12+3(27/10)=0
We add all the numbers together, and all the variables
y-12+3(+27/10)=0
We multiply parentheses
y-12+27/10*3=0
We multiply all the terms by the denominator
y*10*3+27-12*10*3=0
We add all the numbers together, and all the variables
y*10*3-333=0
Wy multiply elements
30y*3-333=0
Wy multiply elements
90y-333=0
We move all terms containing y to the left, all other terms to the right
90y=333
y=333/90
y=3+7/10

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