3(29+5)+(3a+1)=109

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Solution for 3(29+5)+(3a+1)=109 equation: 



3(29+5)+(3a+1)=109

We move all terms to the left:

3(29+5)+(3a+1)-(109)=0

determiningTheFunctionDomain
(3a+1)-109+3(29+5)=0

We add all the numbers together, and all the variables

(3a+1)-109+334=0

We add all the numbers together, and all the variables

(3a+1)+225=0

We get rid of parentheses

3a+1+225=0

We add all the numbers together, and all the variables

3a+226=0

We move all terms containing a to the left, all other terms to the right

3a=-226

a=-226/3

a=-75+1/3

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