3(29+5)=6(7+4q)

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Solution for 3(29+5)=6(7+4q) equation:



3(29+5)=6(7+4q)
We move all terms to the left:
3(29+5)-(6(7+4q))=0
We add all the numbers together, and all the variables
-(6(4q+7))+334=0
We calculate terms in parentheses: -(6(4q+7)), so:
6(4q+7)
We multiply parentheses
24q+42
Back to the equation:
-(24q+42)
We get rid of parentheses
-24q-42+334=0
We add all the numbers together, and all the variables
-24q+292=0
We move all terms containing q to the left, all other terms to the right
-24q=-292
q=-292/-24
q=12+1/6

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