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3(2a+1)-a=3(4a+1)
We move all terms to the left:
3(2a+1)-a-(3(4a+1))=0
We add all the numbers together, and all the variables
-1a+3(2a+1)-(3(4a+1))=0
We multiply parentheses
-1a+6a-(3(4a+1))+3=0
We calculate terms in parentheses: -(3(4a+1)), so:We add all the numbers together, and all the variables
3(4a+1)
We multiply parentheses
12a+3
Back to the equation:
-(12a+3)
5a-(12a+3)+3=0
We get rid of parentheses
5a-12a-3+3=0
We add all the numbers together, and all the variables
-7a=0
a=0/-7
a=0
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