3(2a+1)=4a+173(2a+1)=4a+17

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Solution for 3(2a+1)=4a+173(2a+1)=4a+17 equation:



3(2a+1)=4a+173(2a+1)=4a+17
We move all terms to the left:
3(2a+1)-(4a+173(2a+1))=0
We multiply parentheses
6a-(4a+173(2a+1))+3=0
We calculate terms in parentheses: -(4a+173(2a+1)), so:
4a+173(2a+1)
We multiply parentheses
4a+346a+173
We add all the numbers together, and all the variables
350a+173
Back to the equation:
-(350a+173)
We get rid of parentheses
6a-350a-173+3=0
We add all the numbers together, and all the variables
-344a-170=0
We move all terms containing a to the left, all other terms to the right
-344a=170
a=170/-344
a=-85/172

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