3(2a+1)=4a+173(2a+1)=4a+17

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Solution for 3(2a+1)=4a+173(2a+1)=4a+17 equation: 



3(2a+1)=4a+173(2a+1)=4a+17

We move all terms to the left:

3(2a+1)-(4a+173(2a+1))=0

We multiply parentheses

6a-(4a+173(2a+1))+3=0



We calculate terms in parentheses: -(4a+173(2a+1)), so:

4a+173(2a+1)

We multiply parentheses

4a+346a+173

We add all the numbers together, and all the variables

350a+173

Back to the equation:

-(350a+173)



We get rid of parentheses

6a-350a-173+3=0

We add all the numbers together, and all the variables

-344a-170=0

We move all terms containing a to the left, all other terms to the right

-344a=170

a=170/-344

a=-85/172

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