3(2a+1)=7(3a-5)

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Solution for 3(2a+1)=7(3a-5) equation: 



3(2a+1)=7(3a-5)

We move all terms to the left:

3(2a+1)-(7(3a-5))=0

We multiply parentheses

6a-(7(3a-5))+3=0



We calculate terms in parentheses: -(7(3a-5)), so:

7(3a-5)

We multiply parentheses

21a-35

Back to the equation:

-(21a-35)



We get rid of parentheses

6a-21a+35+3=0

We add all the numbers together, and all the variables

-15a+38=0

We move all terms containing a to the left, all other terms to the right

-15a=-38

a=-38/-15

a=2+8/15

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