3(2a+3)-4(39-6)=15

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Solution for 3(2a+3)-4(39-6)=15 equation: 



3(2a+3)-4(39-6)=15

We move all terms to the left:

3(2a+3)-4(39-6)-(15)=0

determiningTheFunctionDomain
3(2a+3)-15-4(39-6)=0

We add all the numbers together, and all the variables

3(2a+3)-15-433=0

We add all the numbers together, and all the variables

3(2a+3)-448=0

We multiply parentheses

6a+9-448=0

We add all the numbers together, and all the variables

6a-439=0

We move all terms containing a to the left, all other terms to the right

6a=439

a=439/6

a=73+1/6

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