3(2a+3)-4(3a-6)=16

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Solution for 3(2a+3)-4(3a-6)=16 equation: 



3(2a+3)-4(3a-6)=16

We move all terms to the left:

3(2a+3)-4(3a-6)-(16)=0

We multiply parentheses

6a-12a+9+24-16=0

We add all the numbers together, and all the variables

-6a+17=0

We move all terms containing a to the left, all other terms to the right

-6a=-17

a=-17/-6

a=2+5/6

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