3(2a+5)-7=2(4a-5)+3a

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Solution for 3(2a+5)-7=2(4a-5)+3a equation: 



3(2a+5)-7=2(4a-5)+3a

We move all terms to the left:

3(2a+5)-7-(2(4a-5)+3a)=0

We multiply parentheses

6a-(2(4a-5)+3a)+15-7=0



We calculate terms in parentheses: -(2(4a-5)+3a), so:

2(4a-5)+3a

We add all the numbers together, and all the variables

3a+2(4a-5)

We multiply parentheses

3a+8a-10

We add all the numbers together, and all the variables

11a-10

Back to the equation:

-(11a-10)



We add all the numbers together, and all the variables

6a-(11a-10)+8=0

We get rid of parentheses

6a-11a+10+8=0

We add all the numbers together, and all the variables

-5a+18=0

We move all terms containing a to the left, all other terms to the right

-5a=-18

a=-18/-5

a=3+3/5

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