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3(2a+5)=(5a+4)
We move all terms to the left:
3(2a+5)-((5a+4))=0
We multiply parentheses
6a-((5a+4))+15=0
We calculate terms in parentheses: -((5a+4)), so:We get rid of parentheses
(5a+4)
We get rid of parentheses
5a+4
Back to the equation:
-(5a+4)
6a-5a-4+15=0
We add all the numbers together, and all the variables
a+11=0
We move all terms containing a to the left, all other terms to the right
a=-11
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