3(2a+6)+8a=10(a-1)-3a

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Solution for 3(2a+6)+8a=10(a-1)-3a equation: 



3(2a+6)+8a=10(a-1)-3a

We move all terms to the left:

3(2a+6)+8a-(10(a-1)-3a)=0

We add all the numbers together, and all the variables

8a+3(2a+6)-(10(a-1)-3a)=0

We multiply parentheses

8a+6a-(10(a-1)-3a)+18=0



We calculate terms in parentheses: -(10(a-1)-3a), so:

10(a-1)-3a

We add all the numbers together, and all the variables

-3a+10(a-1)

We multiply parentheses

-3a+10a-10

We add all the numbers together, and all the variables

7a-10

Back to the equation:

-(7a-10)



We add all the numbers together, and all the variables

14a-(7a-10)+18=0

We get rid of parentheses

14a-7a+10+18=0

We add all the numbers together, and all the variables

7a+28=0

We move all terms containing a to the left, all other terms to the right

7a=-28

a=-28/7

a=-4

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