3(2a-5)-4a=2(a-3)-5

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Solution for 3(2a-5)-4a=2(a-3)-5 equation: 



3(2a-5)-4a=2(a-3)-5

We move all terms to the left:

3(2a-5)-4a-(2(a-3)-5)=0

We add all the numbers together, and all the variables

-4a+3(2a-5)-(2(a-3)-5)=0

We multiply parentheses

-4a+6a-(2(a-3)-5)-15=0



We calculate terms in parentheses: -(2(a-3)-5), so:

2(a-3)-5

We multiply parentheses

2a-6-5

We add all the numbers together, and all the variables

2a-11

Back to the equation:

-(2a-11)



We add all the numbers together, and all the variables

2a-(2a-11)-15=0

We get rid of parentheses

2a-2a+11-15=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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