3(2a-5)=6+2(a-3)

Solution for 3(2a-5)=6+2(a-3) equation:

3(2a-5)=6+2(a-3)

We move all terms to the left:

3(2a-5)-(6+2(a-3))=0

We multiply parentheses

6a-(6+2(a-3))-15=0


We calculate terms in parentheses: -(6+2(a-3)), so:

6+2(a-3)

determiningTheFunctionDomain
2(a-3)+6

We multiply parentheses

2a-6+6

We add all the numbers together, and all the variables

2a

Back to the equation:

-(2a)


We add all the numbers together, and all the variables

4a-15=0

We move all terms containing a to the left, all other terms to the right

4a=15

a=15/4

a=3+3/4