3(2b+1)=33

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Solution for 3(2b+1)=33 equation: 



3(2b+1)=33

We move all terms to the left:

3(2b+1)-(33)=0

We multiply parentheses

6b+3-33=0

We add all the numbers together, and all the variables

6b-30=0

We move all terms containing b to the left, all other terms to the right

6b=30

b=30/6

b=5

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