3(2b+4)+4(b-2)=54

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Solution for 3(2b+4)+4(b-2)=54 equation: 



3(2b+4)+4(b-2)=54

We move all terms to the left:

3(2b+4)+4(b-2)-(54)=0

We multiply parentheses

6b+4b+12-8-54=0

We add all the numbers together, and all the variables

10b-50=0

We move all terms containing b to the left, all other terms to the right

10b=50

b=50/10

b=5

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