3(2b+4)+5(3-2b)=7-2b

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Solution for 3(2b+4)+5(3-2b)=7-2b equation: 



3(2b+4)+5(3-2b)=7-2b

We move all terms to the left:

3(2b+4)+5(3-2b)-(7-2b)=0

We add all the numbers together, and all the variables

3(2b+4)+5(-2b+3)-(-2b+7)=0

We multiply parentheses

6b-10b-(-2b+7)+12+15=0

We get rid of parentheses

6b-10b+2b-7+12+15=0

We add all the numbers together, and all the variables

-2b+20=0

We move all terms containing b to the left, all other terms to the right

-2b=-20

b=-20/-2

b=+10

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