3(2b+7)=3(b+3)+3

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Solution for 3(2b+7)=3(b+3)+3 equation: 



3(2b+7)=3(b+3)+3

We move all terms to the left:

3(2b+7)-(3(b+3)+3)=0

We multiply parentheses

6b-(3(b+3)+3)+21=0



We calculate terms in parentheses: -(3(b+3)+3), so:

3(b+3)+3

We multiply parentheses

3b+9+3

We add all the numbers together, and all the variables

3b+12

Back to the equation:

-(3b+12)



We get rid of parentheses

6b-3b-12+21=0

We add all the numbers together, and all the variables

3b+9=0

We move all terms containing b to the left, all other terms to the right

3b=-9

b=-9/3

b=-3

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