3(2b-1)-7=2(5b-5)

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Solution for 3(2b-1)-7=2(5b-5) equation: 



3(2b-1)-7=2(5b-5)

We move all terms to the left:

3(2b-1)-7-(2(5b-5))=0

We multiply parentheses

6b-(2(5b-5))-3-7=0



We calculate terms in parentheses: -(2(5b-5)), so:

2(5b-5)

We multiply parentheses

10b-10

Back to the equation:

-(10b-10)



We add all the numbers together, and all the variables

6b-(10b-10)-10=0

We get rid of parentheses

6b-10b+10-10=0

We add all the numbers together, and all the variables

-4b=0

b=0/-4

b=0

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