3(2b-1)=2(b+2)

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Solution for 3(2b-1)=2(b+2) equation: 



3(2b-1)=2(b+2)

We move all terms to the left:

3(2b-1)-(2(b+2))=0

We multiply parentheses

6b-(2(b+2))-3=0



We calculate terms in parentheses: -(2(b+2)), so:

2(b+2)

We multiply parentheses

2b+4

Back to the equation:

-(2b+4)



We get rid of parentheses

6b-2b-4-3=0

We add all the numbers together, and all the variables

4b-7=0

We move all terms containing b to the left, all other terms to the right

4b=7

b=7/4

b=1+3/4

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