3(2b-3)-3(b-7)-12=0

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Solution for 3(2b-3)-3(b-7)-12=0 equation: 



3(2b-3)-3(b-7)-12=0

We multiply parentheses

6b-3b-9+21-12=0

We add all the numbers together, and all the variables

3b=0

b=0/3

b=0

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