3(2b-3)-3(b-7)-12=0

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Solution for 3(2b-3)-3(b-7)-12=0 equation:



3(2b-3)-3(b-7)-12=0
We multiply parentheses
6b-3b-9+21-12=0
We add all the numbers together, and all the variables
3b=0
b=0/3
b=0

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