3(2b-4)=5(b+2)

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Solution for 3(2b-4)=5(b+2) equation:


Simplifying
3(2b + -4) = 5(b + 2)

Reorder the terms:
3(-4 + 2b) = 5(b + 2)
(-4 * 3 + 2b * 3) = 5(b + 2)
(-12 + 6b) = 5(b + 2)

Reorder the terms:
-12 + 6b = 5(2 + b)
-12 + 6b = (2 * 5 + b * 5)
-12 + 6b = (10 + 5b)

Solving
-12 + 6b = 10 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
-12 + 6b + -5b = 10 + 5b + -5b

Combine like terms: 6b + -5b = 1b
-12 + 1b = 10 + 5b + -5b

Combine like terms: 5b + -5b = 0
-12 + 1b = 10 + 0
-12 + 1b = 10

Add '12' to each side of the equation.
-12 + 12 + 1b = 10 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 10 + 12
1b = 10 + 12

Combine like terms: 10 + 12 = 22
1b = 22

Divide each side by '1'.
b = 22

Simplifying
b = 22

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