3(2b-4)=7(b+8)

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Solution for 3(2b-4)=7(b+8) equation: 



3(2b-4)=7(b+8)

We move all terms to the left:

3(2b-4)-(7(b+8))=0

We multiply parentheses

6b-(7(b+8))-12=0



We calculate terms in parentheses: -(7(b+8)), so:

7(b+8)

We multiply parentheses

7b+56

Back to the equation:

-(7b+56)



We get rid of parentheses

6b-7b-56-12=0

We add all the numbers together, and all the variables

-1b-68=0

We move all terms containing b to the left, all other terms to the right

-b=68

b=68/-1

b=-68

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