3(2b-5)+4(3b+2)=11

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Solution for 3(2b-5)+4(3b+2)=11 equation: 



3(2b-5)+4(3b+2)=11

We move all terms to the left:

3(2b-5)+4(3b+2)-(11)=0

We multiply parentheses

6b+12b-15+8-11=0

We add all the numbers together, and all the variables

18b-18=0

We move all terms containing b to the left, all other terms to the right

18b=18

b=18/18

b=1

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