3(2c+1)+20=9c-2(3c-1)

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Solution for 3(2c+1)+20=9c-2(3c-1) equation:


Simplifying
3(2c + 1) + 20 = 9c + -2(3c + -1)

Reorder the terms:
3(1 + 2c) + 20 = 9c + -2(3c + -1)
(1 * 3 + 2c * 3) + 20 = 9c + -2(3c + -1)
(3 + 6c) + 20 = 9c + -2(3c + -1)

Reorder the terms:
3 + 20 + 6c = 9c + -2(3c + -1)

Combine like terms: 3 + 20 = 23
23 + 6c = 9c + -2(3c + -1)

Reorder the terms:
23 + 6c = 9c + -2(-1 + 3c)
23 + 6c = 9c + (-1 * -2 + 3c * -2)
23 + 6c = 9c + (2 + -6c)

Reorder the terms:
23 + 6c = 2 + 9c + -6c

Combine like terms: 9c + -6c = 3c
23 + 6c = 2 + 3c

Solving
23 + 6c = 2 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
23 + 6c + -3c = 2 + 3c + -3c

Combine like terms: 6c + -3c = 3c
23 + 3c = 2 + 3c + -3c

Combine like terms: 3c + -3c = 0
23 + 3c = 2 + 0
23 + 3c = 2

Add '-23' to each side of the equation.
23 + -23 + 3c = 2 + -23

Combine like terms: 23 + -23 = 0
0 + 3c = 2 + -23
3c = 2 + -23

Combine like terms: 2 + -23 = -21
3c = -21

Divide each side by '3'.
c = -7

Simplifying
c = -7

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