3(2c+1)+c=5

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Solution for 3(2c+1)+c=5 equation:


Simplifying
3(2c + 1) + c = 5

Reorder the terms:
3(1 + 2c) + c = 5
(1 * 3 + 2c * 3) + c = 5
(3 + 6c) + c = 5

Combine like terms: 6c + c = 7c
3 + 7c = 5

Solving
3 + 7c = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 7c = 5 + -3

Combine like terms: 3 + -3 = 0
0 + 7c = 5 + -3
7c = 5 + -3

Combine like terms: 5 + -3 = 2
7c = 2

Divide each side by '7'.
c = 0.2857142857

Simplifying
c = 0.2857142857

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