3(2c+1)=2(1-c)-1

Solution for 3(2c+1)=2(1-c)-1 equation:

Simplifying
3(2c + 1) = 2(1 + -1c) + -1

Reorder the terms:
3(1 + 2c) = 2(1 + -1c) + -1
(1 * 3 + 2c * 3) = 2(1 + -1c) + -1
(3 + 6c) = 2(1 + -1c) + -1
3 + 6c = (1 * 2 + -1c * 2) + -1
3 + 6c = (2 + -2c) + -1

Reorder the terms:
3 + 6c = 2 + -1 + -2c

Combine like terms: 2 + -1 = 1
3 + 6c = 1 + -2c

Solving
3 + 6c = 1 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
3 + 6c + 2c = 1 + -2c + 2c

Combine like terms: 6c + 2c = 8c
3 + 8c = 1 + -2c + 2c

Combine like terms: -2c + 2c = 0
3 + 8c = 1 + 0
3 + 8c = 1

Add '-3' to each side of the equation.
3 + -3 + 8c = 1 + -3

Combine like terms: 3 + -3 = 0
0 + 8c = 1 + -3
8c = 1 + -3

Combine like terms: 1 + -3 = -2
8c = -2

Divide each side by '8'.
c = -0.25

Simplifying
c = -0.25